differentiation

Question: If ${x^{2/3}} + {y^{2/3}} = {a^{2/3}}$, then $\frac{{dy}}{{dx}} = $



1) ${\left( {\frac{y}{x}} \right)^{1/3}}$
2) $ - {\left( {\frac{y}{x}} \right)^{1/3}}$
3) ${\left( {\frac{x}{y}} \right)^{1/3}}$
4) $ - {\left( {\frac{x}{y}} \right)^{1/3}}$
Solution: Explanation: Explanation
standard-differentiation

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