Questions in indefinite-integration

Select	Question
	$\int_{{}}^{{}}{\frac{dx}{4{{x}^{2}}+9}=}$
	$\int_{{}}^{{}}{\sqrt{1+{{x}^{2}}}\ dx=}$
	$\int_{{}}^{{}}{\frac{dx}{\sqrt{{{x}^{2}}-{{a}^{2}}}}}$ equals
	$\int{\frac{{{x}^{2}}}{{{x}^{2}}+4}\,\,dx}$ equals to
	$\int{\sqrt{{{x}^{2}}+{{a}^{2}}}\,\,dx}$ equals to
	$\int{\frac{dx}{{{a}^{2}}-{{x}^{2}}}}$ is equal to
	$\int_{{}}^{{}}{\frac{dx}{\sqrt{{{x}^{2}}+{{a}^{2}}}}}$ is equal to
	$\int_{{}}^{{}}{\frac{dx}{1+{{e}^{x}}}=}$
	$\int_{{}}^{{}}{\frac{dx}{{{e}^{x}}+{{e}^{-x}}}=}$
	$\int_{{}}^{{}}{\frac{{{e}^{\sqrt{x}}}\cos {{e}^{\sqrt{x}}}}{\sqrt{x}}dx}=$