Questions in indefinite-integration

Select	Question
	$\int_{{}}^{{}}{\frac{dx}{x+x\log x}=}$
	To find the value of $\int_{{}}^{{}}{\frac{1+\log x}{x}\text{ }}dx$, the proper substitution is
	$\int_{{}}^{{}}{\frac{\sec x\ dx}{\sqrt{\cos 2x}}}=$
	To find the value of $\int_{{}}^{{}}{\frac{dx}{x\sqrt{2ax-{{x}^{2}}}}}$, the suitable substitution is
	$\int_{{}}^{{}}{\frac{x\ dx}{1-x\cot x}}=$
	$\int_{{}}^{{}}{\frac{\sin 2x}{1+{{\sin }^{2}}x}dx=}$
	$\int_{{}}^{{}}{\frac{{{x}^{3}}}{\sqrt{{{x}^{2}}+2}}dx=}$
	$\int_{{}}^{{}}{\frac{{{x}^{e-1}}+{{e}^{x-1}}}{{{x}^{e}}+{{e}^{x}}}dx=}$
	$\int_{{}}^{{}}{\frac{\sin x\ dx}{{{a}^{2}}+{{b}^{2}}{{\cos }^{2}}x}}=$
	$\int_{{}}^{{}}{\sec x\log (\sec x+\tan x)\ dx=}$