Categories > indefinite-integration > Integration by substitution > $\int_{{}}^{{}}{\frac{{{x}^{3}}}{\sqrt{{{x}^{2}}+2}}dx=}$

indefinite-integration

Question: $\int_{{}}^{{}}{\frac{{{x}^{3}}}{\sqrt{{{x}^{2}}+2}}dx=}$


1) $\frac{1}{3}{{({{x}^{2}}+2)}^{3/2}}+2{{({{x}^{2}}+2)}^{1/2}}+c$
2) $\frac{1}{3}{{({{x}^{2}}+2)}^{3/2}}-2{{({{x}^{2}}+2)}^{1/2}}+c$
3) $\frac{1}{3}{{({{x}^{2}}+2)}^{3/2}}+{{({{x}^{2}}+2)}^{1/2}}+c$
4) $\frac{1}{3}{{({{x}^{2}}+2)}^{3/2}}-{{({{x}^{2}}+2)}^{1/2}}+c$
Solution: Explanation: No Explanation
Integration by substitution

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)

Previous Question Next Question

Related Questions