Questions in gravitation

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At what height from the ground will the value of ‘g’ be the same as that in 10 km deep mine below the surface of earth
If the Earth losses its gravity, then for a body
The height of the point vertically above the earth’s surface, at which acceleration due to gravity becomes 1% of its value at the surface is (Radius of the earth = R)
An object weights 72 N on earth. Its weight at a height of R/2 from earth is
The angular velocity of the earth with which it has to rotate so that acceleration due to gravity on 60o latitude becomes zero is (Radius of earth = 6400 km. At the poles $g = 10\,m{s^{ - 2}})$
Assuming earth to be a sphere of a uniform density, what is the value of gravitational acceleration in a mine 100 km below the earth’s surface (Given R = 6400 km)
If radius of earth is R then the height ‘h’ at which value of ‘g’ becomes one-fourth is
R and r are the radii of the earth and moon respectively. ${\rho _e}$ and ${\rho _m}$ are the densities of earth and moon respectively. The ratio of the accelerations due to gravity on the surfaces of earth and moon is
If the mass of earth is 80 times of that of a planet and diameter is double that of planet and ‘g’ on earth is $9.8\,m/{s^2}$, then the value of ‘g’ on that planet is
Assume that the acceleration due to gravity on the surface of the moon is 0.2 times the acceleration due to gravity on the surface of the earth. If ${R_e}$ is the maximum range of a projectile on the earth’s surface, what is the maximum range on the surface of the moon for the same velocity of projection

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