Questions in gravitation

Select	Question
	Weight of 1 kg becomes 1/6 on moon. If radius of moon is $1.768 imes {10^6}\,m$, then the mass of moon will be
	Radius of earth is around 6000 km. The weight of body at height of 6000 km from earth surface becomes
	Let g be the acceleration due to gravity at earth's surface and K be the rotational kinetic energy of the earth. Suppose the earth's radius decreases by 2% keeping all other quantities same, then
	Where will it be profitable to purchase 1 kilogram sugar
	If the radius of the earth shrinks by 1.5% (mass remaining same), then the value of acceleration due to gravity changes by
	If radius of the earth contracts 2% and its mass remains the same, then weight of the body at the earth surface
	If mass of a body is M on the earth surface, then the mass of the same body on the moon surface is
	Mass of moon is $7.34 \times {10^{22}}$kg. If the acceleration due to gravity on the moon is $1.4\,m/{s^2}$, the radius of the moon is $(G = 6.667 \times {10^{ - 11}}\,N{m^2}/k{g^2})$
	What should be the velocity of earth due to rotation about its own axis so that the weight at equator become 3/5 of initial value. Radius of earth on equator is 6400 km
	Acceleration due to gravity is ‘g’ on the surface of the earth. The value of acceleration due to gravity at a height of 32 km above earth’s surface is (Radius of the earth = 6400 km)