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The acceleration due to gravity at pole and equator can be related as
If the value of ‘g’ acceleration due to gravity, at earth surface is $10\,m/{s^2}$, its value in $m/{s^2}$ at the centre of the earth, which is assumed to be a sphere of radius ‘R’ metre and uniform mass density is
A research satellite of mass 200 kg circles the earth in an orbit of average radius 3R/2 where R is the radius of the earth. Assuming the gravitational pull on a mass of 1 kg on the earth’s surface to be 10 N, the pull on the satellite will be
Acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth. If the ratio of densities of earth $({\rho _e})$ and moon $({\rho _m})$ is $\left( {\frac{{{\rho _e}}}{{{\rho _m}}}} \right) = \frac{5}{3}$ then radius of moon Rm in terms of Re will be
The acceleration of a body due to the attraction of the earth (radius R) at a distance 2 R from the surface of the earth is (g = acceleration due to gravity at the surface of the earth)
The depth at which the effective value of acceleration due to gravity is $\frac{g}{4}$ is
Weight of a body of mass m decreases by 1% when it is raised to height h above the earth’s surface. If the body is taken to a depth h in a mine, change in its weight is
If both the mass and the radius of the earth decrease by 1%, the value of the acceleration due to gravity will
The density of a newly discovered planet is twice that of earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth is R, the radius of the planet would be
Two planets of radii in the ratio 2 : 3 are made from the material of density in the ratio 3 : 2. Then the ratio of acceleration due to gravity ${g_1}/{g_2}$ at the surface of the two planets will be

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