Questions in definite-integral

Select	Question
	Assume that $f$ is continuous everywhere, then $\frac{1}{c}\int_{ac}^{bc}{f\left( \frac{x}{c} \right)}\,dx=$
	$\int_{\,-1/2}^{\,1/2}{(\cos x)\,\left[ \log \left( \frac{1-x}{1+x} \right) \right]\,dx=}$
	The value of $\int_{\,0}^{\,1}{\,\frac{dx}{x+\sqrt{1-{{x}^{2}}}}}$ is
	If $\int_{-1}^{1}{f(x)\,dx=0}$, then
	$\int_{-1}^{1}{\|1-x\|dx}=$
	If n is a positive integer and [x] is the greatest integer not exceeding x, then $\int_{0}^{n}{\,\,\{x-[x]\}\,dx}$ equals
	$\int_{0}^{\pi }{x{{\sin }^{3}}x\,dx}=$
	$\int_{-2}^{2}{\|1-{{x}^{2}}\|\,dx=}$
	$\int_{0}^{\pi /2}{\frac{\sqrt{\cos x}}{\sqrt{\sin x}+\sqrt{\cos x}}\,dx=}$
	$\int_{0}^{\pi /2}{\frac{x\sin x\cos x}{{{\cos }^{4}}x+{{\sin }^{4}}x}}\,dx=$