definite-integral

Question: The value of $\int_{\,0}^{\,1}{\,\frac{dx}{x+\sqrt{1-{{x}^{2}}}}}$ is



1) $\frac{\pi }{3}$
2) $\frac{\pi }{2}$
3) $\frac{1}{2}$
4) $\frac{\pi }{4}$
Solution: Explanation: No Explanation
Properties of definite integration

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