Questions in Mechanical Properties of Fluids

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Energy needed in breaking a drop of radius $R$ into $n$ drops of radii $r$ is given by
The potential energy of a molecule on the surface of liquid compared to one inside the liquid is
Two droplets merge with each other and forms a large droplet. In this process
A drop of liquid of diameter 2.8 mm breaks up into 125 identical drops. The change in energy is nearly (S.T. of liquid =75 dynes/cm)
Radius of a soap bubble is $r$, surface tension of soap solution is $T$. Then without increasing the temperature, how much energy will be needed to double its radius
Work done in splitting a drop of water of 1 mm radius into 106 droplets is (Surface tension of water $=72 \times {{10}^{-3}}J/{{m}^{2}})$
A spherical liquid drop of radius R is divided into eight equal droplets. If surface tension is $T$, then the work done in this process will be
The amount of work done in blowing a soap bubble such that its diameter increases from $d$ to $D$ is (T= surface tension of the solution)
If $T$ is the surface tension of soap solution, the amount of work done in blowing a soap bubble from a diameter $D$ to $2D$ is
The radius of a soap bubble is increased from $\frac{1}{\sqrt{\pi }}$ cm to $\frac{2}{\sqrt{\pi }}$ cm. If the surface tension of water is 30 dynes per cm, then the work done will be

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