Mechanical Properties of Fluids

Question: Energy needed in breaking a drop of radius $R$ into $n$ drops of radii $r$ is given by

1) $4\pi T(n{{r}^{2}}-{{R}^{2}})$

2) $\frac{4}{3}\pi ({{r}^{3}}n-{{R}^{2}})$

3) $4\pi T({{R}^{2}}-n{{r}^{2}})$

4) $4\pi T(n{{r}^{2}}+{{R}^{2}})$

Solution:

Explanation: No Explanation

Surface tension surface energy

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