Questions in Mechanical Properties of Fluids

Select	Question
	The surface tension of liquid is $0.5 N/m$. If a film is held on a ring of area $0.02 m^2$, its surface energy is
	What is ratio of surface energy of 1 small drop and 1 large drop, if 1000 small drops combined to form 1 large drop
	The amount of work done in forming a soap film of size $10\,cm\times 10\,cm$is (Surface tension $T=3\times {{10}^{-2}}\,N/m)$
	The work done in blowing a soap bubble of $10 cm$ radius is (Surface tension of the soap solution is $\frac{3}{100}N/m$)
	A liquid drop of diameter $D$ breaks upto into $27$ small drops of equal size. If the surface tension of the liquid is $\sigma$, then change in surface energy is
	One thousand small water drops of equal radii combine to form a big drop. The ratio of final surface energy to the total initial surface energy is
	The work done in increasing the size of a soap film from $10 cm \times 6 cm$ to $10 cm \times 11 cm$ is $3 \times 10^{-4}$ joule. The surface tension of the film is
	If $\sigma$ be the surface tension, the work done in breaking a big drop of radius $R$ in $n$ drops of equal radius is
	A big drop of radius R is formed by 1000 small droplets of water, then the radius of small drop is
	When ${{10}^{6}}$small drops coalesce to make a new larger drop then the drop