Questions in Electrostatics

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If $q$ is the charge per unit area on the surface of a conductor, then the electric field intensity at a point on the surface is
A hollow conducting sphere of radius $R$ has a charge $( + Q)$ on its surface. What is the electric potential within the sphere at a distance $r = \frac{R}{3}$ from its centre
A spherical conductor of radius 2m is charged to a potential of 120 V. It is now placed inside another hollow spherical conductor of radius 6m. Calculate the potential to which the bigger sphere would be raised
A charge $( - q)$ and another charge $( + Q)$ are kept at two points A and B respectively. Keeping the charge $( + Q)$ fixed at B, the charge $( - q)$ at A is moved to another point C such that ABC forms an equilateral triangle of side l. The net work done in moving the charge $( - q)$ is
A particle of mass ‘m’ and charge ‘q’ is accelerated through a potential difference of V volt, its energy will be
Two spheres A and B of radius ‘a’ and ‘b’ respectively are at same electric potential. The ratio of the surface charge densities of A and B is
Potential at a point x-distance from the centre inside the conducting sphere of radius R and charged with charge Q is
Electric field intensity at a point in between two parallel sheets with like charges of same surface charge densities $(\sigma )$ is
In an hydrogen atom, the electron revolves around the nucleus in an orbit of radius $0.53 \times {10^{ - 10}}m$. Then the electrical potential produced by the nucleus at the position of the electron is
Consider two point charges of equal magnitude and opposite sign separated by a certain distance. The neutral point due to them

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