Electrostatics

Question: A charge $( - q)$ and another charge $( + Q)$ are kept at two points A and B respectively. Keeping the charge $( + Q)$ fixed at B, the charge $( - q)$ at A is moved to another point C such that ABC forms an equilateral triangle of side l. The net work done in moving the charge $( - q)$ is



1) $\frac{1}{{4\pi {\varepsilon _0}}}\frac{{Qq}}{l}$
2) $\frac{1}{{4\pi {\varepsilon _0}}}\frac{{Qq}}{{{l^2}}}$
3) $\frac{1}{{4\pi {\varepsilon _0}}}Qql$
4) Zero
Solution: Explanation: Explanation
electric-field-potential

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