Current Electricity

Question: A copper wire of resistance R is cut into ten parts of equal length. Two pieces each are joined in series and then five such combinations are joined in parallel. The new combination will have a resistance

1) R

2) $\frac{R}{4}$

3) $\frac{R}{5}$

4) $\frac{R}{{25}}$

Solution:

Explanation: No Explanation

Grouping of Resistors Combination of Resistors

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