Electrostatics

Question: A charged particle is suspended in equilibrium in a uniform vertical electric field of intensity 20000 V/m. If mass of the particle is $9.6 \times {10^{ - 16}}\,kg$, the charge on it and excess number of electrons on the particle are respectively $(g = 10\,m/{s^2})$

1) $4.8 \times {10^{ - 19}}C,\,3$

2) $5.8 \times {10^{ - 19}}C,\,4$

3) $3.8 \times {10^{ - 19}}C,\,2$

4) $2.8 \times {10^{ - 19}}C,\,1$

Solution:

Explanation: Explanation

electric-field-potential

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