Electrostatics

Question: What is the magnitude of a point charge which produces an electric field of 2 N/coulomb at a distance of 60 cm ($1/4\pi {\varepsilon _0} = 9 \times {10^9}N - {m^2}/{C^2}$)



1) $8 \times {10^{ - 11}}$C
2) $2 \times {10^{ - 12}}$C
3) $3 \times {10^{ - 11}}$C
4) $6 \times {10^{ - 10}}$C
Solution: Explanation: Explanation
electric-field-potential

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