Current Electricity

Question: If $n,\,e,\,\tau$ and m respectively represent the density, charge relaxation time and mass of the electron, then the resistance of a wire of length $l$ and area of cross-section $A$ will be

1) $\frac{{ml}}{{n{e^2}\tau A}}$

2) $\frac{{m{\tau ^2}A}}{{n{e^2}l}}$

3) $\frac{{n{e^2}\tau A}}{{2ml}}$

4) $\frac{{n{e^2}A}}{{2m\tau l}}$

Solution:

Explanation: No Explanation

Electric Conduction Ohm's Law Resistance

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