Electrostatics

Question: A charged particle of mass 0.003 gm is held stationary in space by placing it in a downward direction of electric field of $6 \times {10^4}N/C$. Then the magnitude of the charge is

1) $5 \times {10^{ - 4}}C$

2) $5 \times {10^{ - 10}}C$

3) $- 18 \times {10^{ - 6}}C$

4) $- 5 \times {10^{ - 9}}C$

Solution:

Explanation: Explanation

electric-field-potential

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