Electrostatics

Question: An oil drop having charge $2e$ is kept stationary between two parallel horizontal plates 2.0 cm apart when a potential difference of 12000 volts is applied between them. If the density of oil is $900 kg/m^3$, the radius of the drop will be



1) $2.0 \times {10^{ - 6}}m$
2) $1.7 \times {10^{ - 6}}m$
3) $1.4 \times {10^{ - 6}}m$
4) $1.1 \times {10^{ - 6}}m$
Solution: Explanation: Explanation
electric-field-potential

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