Electrostatics

Question: Three charges $Q,( + q)$ and $( + q)$ are placed at the vertices of an equilateral triangle of side l as shown in the figure. If the net electrostatic energy of the system is zero, then Q is equal to



1) $\left( { - \frac{q}{2}} \right)$
2) $( - q)$
3) $( + q)$
4) Zero
Solution: Explanation: Explanation
electric-field-potential

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