Electrostatics

Question: The acceleration of an electron in an electric field of magnitude 50 V/cm, if e/m value of the electron is $1.76 \times {10^{11}}$ C/kg, is

1) $8.8 \times {10^{14}} m/sec^2$

2) $6.2 \times {10^{13}} m/sec^2$

3) $5.4 \times {10^{12}} m/sec^2$

4) Zero

Solution:

Explanation: Explanation

electric-field-potential

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