Electrostatics

Question: An electron of mass $m$ and charge $e$ is accelerated from rest through a potential difference V in vacuum. The final speed of the electron will be



1) $V\sqrt {e/m} $
2) $\sqrt {eV/m} $
3) $\sqrt {2eV/m} $
4) $2eV/m$
Solution: Explanation: Explanation
electric-field-potential

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