Electrostatics

Question: The electric potential $V$ is given as a function of distance $x$ (metre) by $V = (5{x^2} + 10x - 9)\,volt$. Value of electric field at $x = 1$ is



1) $20\,V/m$
2) $6\,V/m$
3) $11\,V/m$
4) $- 23\,V/m$
Solution: Explanation: Explanation
electric-field-potential

Rate this question:

Average rating: (0 votes)

Previous Question Next Question