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Question: The activity of a sample of a radioactive material is A, at time ${t_1}$ and ${A_2}$ at time ${t_2}$ $({t_2} > {t_1}).$ If its mean life is T, then

1) ${A_1}{t_1} = {A_2}{t_2}$

2) ${A_1} - {A_2} = {t_2} - {t_1}$

3) ${A_2} = {A_1}{e^{({t_1} - {t_2})/T}}$

4) ${A_2} = {A_1}{e^{({t_1}/{t_2})T}}$

Solution:

Explanation: No Explanation

Radioactivity Modern Physics

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