Nuclei

Question: If $_{92}{U^{238}}$ undergoes successively 8 $\alpha$ -decays and 6 $\beta$ -decays, then resulting nucleus is

1) $_{82}{U^{206}}$

2) $_{82}P{b^{206}}$

3) $_{82}{U^{210}}$

4) $_{82}{U^{214}}$

Solution:

Explanation: No Explanation

Radioactivity Modern Physics

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