In the visible region of the spectrum the rotation of the place of polarization is given by $ heta = a + \frac{b}{{{\lambda ^2}}}$. The optical rotation produced by a particular material is found to be 30° per mm at $\lambda = 5000$Å and 50° per mm at $\lambda = 4000{ m{{\AA}}}$. The value of constant a will be

Question

In the visible region of the spectrum the rotation of the place of polarization is given by $	heta = a + \frac{b}{{{\lambda ^2}}}$. The optical rotation produced by a particular material is found to be 30° per mm at $\lambda = 5000$Å and 50° per mm at $\lambda = 4000{m{{\AA}}}$. The value of constant a will be

Accepted Answer

$ - \frac{{50^\circ }}{9}$per mm

Answer

$ + \frac{{50^\circ }}{9}$per mm

Answer

$ + \frac{{9^\circ }}{{50}}$per mm

Answer

$ - \frac{{9^\circ }}{{50}}$per mm

wave-optics

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