wave-optics

Question: In the far field diffraction pattern of a single slit under polychromatic illumination, the first minimum with the wavelength ${\lambda _1}$ is found to be coincident with the third maximum at ${\lambda _2}$. So

1) $3{\lambda _1} = 0.3{\lambda _2}$

2) $3{\lambda _1} = {\lambda _2}$

3) ${\lambda _1} = 3.5{\lambda _2}$

4) $0.3{\lambda _1} = 3{\lambda _2}$

Solution:

Explanation: No Explanation

Diffraction of Light

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