wave-optics

Question: In Young's double slit experiment, the distance between sources is 1 mm and distance between the screen and source is 1 m. If the fringe width on the screen is 0.06 cm, then $\lambda$ =



1) 6000 Å
2) 4000 Å
3) 1200 Å
4) 2400 Å
Solution: Explanation: No Explanation
Young's Double Slit Experiment YDSE

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