Categories > wave-optics > Young's Double Slit Experiment > In Young's double slit experiment, the fringe width is $1 \times {10^{ - 4}}m$if the distance between the slit and screen is doubled and the distance between the two slit is reduced to half and wavelength is changed from $6.4 \times {10^7}m$ to $4.0 \times {10^{ - 7}}m$, the value of new fringe width will be

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Question: In Young's double slit experiment, the fringe width is $1 \times {10^{ - 4}}m$if the distance between the slit and screen is doubled and the distance between the two slit is reduced to half and wavelength is changed from $6.4 \times {10^7}m$ to $4.0 \times {10^{ - 7}}m$, the value of new fringe width will be


1) $0.15 \times {10^{ - 4}}m$
2) $2.0 \times {10^{ - 4}}m$
3) $1.25 \times {10^{ - 4}}m$
4) $2.5 \times {10^{ - 4}}m$
Solution: Explanation: No Explanation
Young's Double Slit Experiment YDSE

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