diff-equation

Question: If $\frac{dy}{dx}+\frac{1}{\sqrt{1-{{x}^{2}}}}=0$, then

1) $y+{{\sin }^{-1}}x=c$

2) ${{y}^{2}}+2{{\sin }^{-1}}x+c=0$

3) $x+{{\sin }^{-1}}y=0$

4) ${{x}^{2}}+2{{\sin }^{-1}}y=1$

Solution:

Explanation: No Explanation

Variable separable type differential equations

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