diff-equation

Question: The solution of the equation $(1+{{x}^{2}})\frac{dy}{dx}=1$is



1) $y=\log (1+{{x}^{2}})+c$
2) $y+\log (1+{{x}^{2}})+c=0$
3) $y-\log (1+x)=c$
4) $y={{\tan }^{-1}}x+c$
Solution: Explanation: No Explanation
Variable separable type differential equations

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