diff-equation

Question: The solution of the differential equation $\frac{dy}{dx}+\frac{1+{{x}^{2}}}{x}=0$ is



1) $y=-\frac{1}{2}{{\tan }^{-1}}x+c$
2) $y+\log x+\frac{{{x}^{2}}}{2}+c=0$
3) $y=\frac{1}{2}{{\tan }^{-1}}x+c$
4) $y-\log x-\frac{{{x}^{2}}}{2}=c$
Solution: Explanation: No Explanation
Variable separable type differential equations

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