diff-equation

Question: If $\frac{dy}{dx}={{e}^{-2y}}$ and $y=0$ when $x=5,$ the value of x for $y=3$ is



1) ${{e}^{5}}$
2) ${{e}^{6}}+1$
3) $\frac{{{e}^{6}}+9}{2}$
4) ${{\log }_{e}}6$
Solution: Explanation: No Explanation
Variable separable type differential equations

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