diff-equation

Question: The solution of the differential equation $\frac{dy}{dx}=\frac{1+{{y}^{2}}}{1+{{x}^{2}}}$ is



1) $1+xy+c(y+x)=0$
2) $x+y=c(1-xy)$
3) $y-x=c(1+xy)$
4) $1+xy=c(x+y)$
Solution: Explanation: No Explanation
Variable separable type differential equations

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