diff-equation

Question: The solution of the equation $(2y-1)\,\,dx-(2x+3)\,dy=0$ is



1) $\frac{2x-1}{2y+3}=c$
2) $\frac{2y+1}{2x-3}=c$
3) $\frac{2x+3}{2y-1}=c$
4) $\frac{2x-1}{2y-1}=c$
Solution: Explanation: No Explanation
Variable separable type differential equations

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