diff-equation

Question: The differential equation obtained on eliminating A and B from the equation $y=A\cos \omega t+B\sin \omega t$ is



1) ${y}''=-{{\omega }^{2}}y$
2) ${y}''+y=0$
3) ${y}''+{y}'=0$
4) ${y}''-{{\omega }^{2}}y=0$
Solution: Explanation: No Explanation
Formation of differential equations

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