definite-integral

Question: The part of circle ${{x}^{2}}+{{y}^{2}}=9$ in between $y=0$ and $y=2$ is revolved about y-axis. The volume of generating solid will be



1) $\frac{46}{3}\pi $
2) $12\pi $
3) $16\pi $
4) $28\pi $
Solution: Explanation: No Explanation
Area bounded by region Volume and surface area of solids of revolution

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