definite-integral

Question: The area in the first quadrant between ${{x}^{2}}+{{y}^{2}}={{\pi }^{2}}$ and $y=\sin x$ is



1) $\frac{({{\pi }^{3}}-8)}{4}$
2) $\frac{{{\pi }^{3}}}{4}$
3) $\frac{({{\pi }^{3}}-16)}{4}$
4) $\frac{({{\pi }^{3}}-8)}{2}$
Solution: Explanation: No Explanation
Area bounded by region Volume and surface area of solids of revolution

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