definite-integral

Question: The area enclosed between the parabolas ${{y}^{2}}=4x$ and ${{x}^{2}}=4y$ is



1) $\frac{14}{3}$ sq. unit
2) $\frac{3}{4}$ sq. unit
3) $\frac{3}{16}$ sq. unit
4) $\frac{16}{3}$ sq. unit
Solution: Explanation: No Explanation
Area bounded by region Volume and surface area of solids of revolution

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