definite-integral

Related Questions

• The area bounded by the curve $y=f(x)$, x-axis and ordinates x = 1 and $x=b$is $\frac{5}{24}\pi $, then $f(x)$ is

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• Let $f(x)$ be a non-negative continous function such that the area bounded by the curve $y=f(x)$, x-axis and the ordinates $x=\frac{\pi }{4}$, $x=\beta >\frac{\pi }{4}$ is $\left( \beta \sin \beta +\frac{\pi }{4}\cos \beta +\sqrt{2}\beta \right)$. Then $f\ \left( \frac{\pi }{2} \right)$ is

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• $\int_{0}^{\pi /2}{{{\sin }^{5}}x\,dx=}$

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• Area under the curve $y=\sqrt{3x+4}$ between $x=0$ and $x=4,$ is

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• $\int_{\,0}^{\,\pi }{\sqrt{\frac{1+\cos 2x}{2}}\,dx}$ is equal to

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