definite-integral

Question: The area bounded by the parabola ${{y}^{2}}=4ax,$ its axis and two ordinates $x=4,$ $x=9$ is



1) $4{{a}^{2}}$
2) $4{{a}^{2}}.4$
3) $4{{a}^{2}}(9-4)$
4) $\frac{152\sqrt{a}}{3}$
Solution: Explanation: No Explanation
Area bounded by region Volume and surface area of solids of revolution

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