definite-integral

Question: $\int_{\,0}^{\,1}{\frac{d}{dx}\left[ {{\sin }^{-1}}\left( \frac{2x}{1+{{x}^{2}}} \right) \right]\,dx}$ is equal to



1) 0
2) $\pi $
3) $\pi /2$
4) $\pi /4$
Solution: Explanation: No Explanation
Summation of series by definite Integration

Rate this question:

Average rating: (0 votes)

Previous Question Next Question