definite-integral

Question: $\int_{0}^{1}{\frac{{{e}^{x}}(x-1)}{{{(x+1)}^{3}}}\,dx=}$



1) $\frac{e}{4}$
2) $\frac{e}{4}-1$
3) $\frac{e}{4}+1$
4) None of these
Solution: Explanation: No Explanation
Fundamental definite integration Definite integration by substitution

Rate this question:

Average rating: (0 votes)

Previous Question Next Question