Categories > definite-integral > Fundamental definite integration > $\int_{0}^{a}{\frac{{{x}^{4}}\,dx}{{{({{a}^{2}}+{{x}^{2}})}^{4}}}}=$

definite-integral

Question: $\int_{0}^{a}{\frac{{{x}^{4}}\,dx}{{{({{a}^{2}}+{{x}^{2}})}^{4}}}}=$


1) $\frac{1}{16{{a}^{3}}}\left( \frac{\pi }{4}-\frac{1}{3} \right)$
2) $\frac{1}{16{{a}^{3}}}\left( \frac{\pi }{4}+\frac{1}{3} \right)$
3) $\frac{1}{16}{{a}^{3}}\left( \frac{\pi }{4}-\frac{1}{3} \right)$
4) $\frac{1}{16}{{a}^{3}}\left( \frac{\pi }{4}+\frac{1}{3} \right)$
Solution: Explanation: No Explanation
Fundamental definite integration Definite integration by substitution

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