definite-integral

Question: $\int_{0}^{1}{\frac{{{\tan }^{-1}}x}{1+{{x}^{2}}}}\,dx=$



1) $\frac{{{\pi }^{2}}}{8}$
2) $\frac{{{\pi }^{2}}}{16}$
3) $\frac{{{\pi }^{2}}}{4}$
4) $\frac{{{\pi }^{2}}}{32}$
Solution: Explanation: No Explanation
Fundamental definite integration Definite integration by substitution

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