definite-integral

Question: If $\int_{0}^{k}{\frac{dx}{2+8{{x}^{2}}}}=\frac{\pi }{16}\,,$ then $k=$



1) 1
2) $\frac{1}{2}$
3) $\frac{1}{4}$
4) None of these
Solution: Explanation: No Explanation
Fundamental definite integration Definite integration by substitution

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