definite-integral

Question: $\int_{1}^{2}{\frac{1}{{{x}^{2}}}{{e}^{\frac{-1}{x}}}\,dx=}$



1) $\sqrt{e}+1$
2) $\sqrt{e}-1$
3) $\frac{\sqrt{e}+1}{e}$
4) $\frac{\sqrt{e}-1}{e}$
Solution: Explanation: No Explanation
Fundamental definite integration Definite integration by substitution

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