indefinite-integration

Question: $\int_{{}}^{{}}{{{e}^{{{\tan }^{-1}}x}}}\left( \frac{1+x+{{x}^{2}}}{1+{{x}^{2}}} \right)\ dx$ is equal to

1) $x{{e}^{{{\tan }^{-1}}x}}+c$

2) ${{x}^{2}}{{e}^{{{\tan }^{-1}}x}}+c$

3) $\frac{1}{x}{{e}^{{{\tan }^{-1}}x}}+c$

4) None of these

Solution:

Explanation: No Explanation

Integration by parts

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