$\int_{{}}^{{}}{{{e}^{x}}\left[ {{\sin }^{-1}}\frac{x}{a}+\frac{1}{\sqrt{{{a}^{2}}-{{x}^{2}}}} \right]dx=}$

Question

Accepted Answer

${{e}^{x}}{{\sin }^{-1}}\frac{x}{a}+c$

Answer

$\frac{1}{a}{{e}^{x}}{{\sin }^{-1}}\frac{x}{a}+c$

Answer

$a{{e}^{x}}{{\sin }^{-1}}\frac{x}{a}+c$

Answer

$\frac{{{e}^{x}}}{\sqrt{{{a}^{2}}-{{x}^{2}}}}+c$

indefinite-integration